(1/6)^x=36^-3x-2

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Solution for (1/6)^x=36^-3x-2 equation: 



(1/6)^x=36^-3x-2

We move all terms to the left:

(1/6)^x-(36^-3x-2)=0



Domain of the equation: 6)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/6)^x-(36^-3x-2)=0

We get rid of parentheses

(+1/6)^x+3x+2-36^=0

We multiply all the terms by the denominator


(+1+3x*6)^x+2*6)^x-36^*6)^x=0

We add all the numbers together, and all the variables

(3x*6+1)^x+2*6)^x-36^*6)^x=0

Wy multiply elements

72x^2+(3x*6+1)^x=0

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